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145
es
ua
C
e
ma
n
ed
oc
kc
eh
C
ed
oc
kc
eh
C
In
do
or
fa
n
m
ot
or
e
rr
or
1.
Wi
rin
g e
rro
r of
fa
n m
ot
or
c
on
ne
ct
or
2.
F
an
m
ot
or
e
rro
r
3.
Indo
or
P.
C
. b
oa
rd
e
rro
r
* Dete
ctab
le
in
m
od
el
e
qu
ip
pe
d
w
ith
D
C
fa
n
m
ot
or
(4
-w
ay
c
as
se
tte
, 2
-wa
y c
as
se
tte
, 1
-way
c
as
se
tte
,
co
nc
ea
le
d d
uc
t, w
al
l a
nd
c
ei
lin
g t
yp
es
)
Tu
rn
o
ff
po
w
er
s
up
pl
y.
Y
es
No
No
No
Ye
s
Is
the
re
co
nn
ec
tio
n e
rro
r o
r
dis
co
nn
ec
tio
n o
n c
on
ne
cto
r
CN
33
3,
CN
33
4 o
f in
do
or
P
.C
.
bo
ar
d (
MC
C-
14
02
)?
R
em
ov
e
co
nn
ec
to
rs
C
N
33
3
an
d
C
N
33
4
on
in
do
or
P
.C
. b
oa
rd
(M
C
C
-1
40
2)
.
D
oe
s
fa
n
tu
rn
w
ith
ou
t t
ro
ub
le
w
he
n
tu
rni
ng
it
w
ith
ha
nd
s?
Is
re
sis
ta
nc
e
va
lue
bet
wee
n e
ac
h p
has
e
at
m
oto
r s
ide
o
f fa
n m
oto
r c
on
ne
cto
r
CN
333
on
in
do
or
P
.C
.
bo
ar
d (
M
CC
-14
02
)
cor
re
ct?
*1
Ye
s
No
No
Is
re
si
st
an
ce
va
lu
e
at
m
ot
or
s
id
e
of
fa
n
m
ot
or
c
on
ne
ct
or
C
N
33
4
on
in
do
or
P
.C
. b
oa
rd
(M
C
C
-
14
02
) c
or
re
ct
?
*2
Is
o
ut
pu
t
of
in
do
or
fa
n
m
ot
or
po
si
tio
n
de
te
ct
iv
e
si
gn
al
co
rrec
t?
*3
Y
es
*1
•
Is
n
ot
w
in
di
ng
1
(Re
d
le
ad
) t
o
3
(W
hi
te
le
ad
),
3
(W
hi
te
le
ad
) t
o
5
(B
la
ck
le
ad
),
5
(B
la
ck
le
ad
)
to
1
(R
ed
le
ad
) o
pe
ne
d/
sh
or
te
d?
R
es
is
ta
nc
e v
al
ue
s
ho
ul
d s
at
is
fy
th
e fo
llo
w
s.
[4-way
Cas
sette ty
pe
]
A
P00
7
to
A
P0
30
: A
pp
ro
x.
7
0
to
1
00
A
P0
36
to
A
P0
56
: A
pp
ro
x.
3
5
to
5
0
[2-way
Cas
sette ty
pe
]
A
P0
07
to
A
P0
15
: A
pp
ro
x.
7
0
to
1
00
A
P0
18
to
A
P0
30
: A
pp
ro
x.
3
0
to
7
0
A
P0
36
to
A
P0
56
: A
pp
ro
x.
2
0
to
5
0
[1-way
Cas
sette ty
pe
]
A
pp
ro
x.
3
0
to
7
0
[C
ei
lin
g t
yp
e]
A
P0
15
to
A
P0
27
: A
pp
ro
x.
3
0
to
7
0
A
P0
36
to
A
P0
56
: A
pp
ro
x.
2
0
to
5
0
[W
al
l a
nd
c
on
ce
al
ed
d
uc
t t
yp
es
]
A
pp
ro
x.
1
5
to
3
5
•
Is
n
ot
g
ro
un
de
d
be
tw
ee
n
ca
bi
ne
t a
nd
1
, 3
, 5
?
S
ho
ul
d b
e
10
M
or
mor
e.
*2 C
he
ck
re
si
st
an
ce
v
al
ue
o
f f
an
m
ot
or
p
os
iti
on
d
et
ec
tiv
e
ci
rc
ui
t.
•
Is
n
ot
w
in
di
ng
1
(Y
el
lo
w
le
ad
) t
o
4
(P
in
k
le
ad
)
op
en
ed
/ s
ho
rte
d?
Res
is
ta
nc
e
sh
ou
ld
b
e
5
to
2
0
k
.
*3 C
he
ck
fa
n
m
ot
or
p
os
iti
on
d
et
ect
ive
s
ig
na
l.
•
M
ea
su
re
v
ol
ta
ge
w
ith
te
st
er
b
et
w
ee
n
1
an
d
5
of
C
N
33
4
on
in
do
or
P
.C
. b
oa
rd
(M
C
C
-1
40
2,
M
C
C
-1
57
0)
u
nd
er
c
on
di
tio
n
of
C
N
33
3
and
C
N
33
4
in
st
al
le
d
an
d
po
w
er
-O
N
.
T
ur
n
fa
n
sl
ow
ly
w
ith
h
an
ds
so
th
at
pi
n
vo
lta
ge
fl
uc
tu
at
es
be
tw
ee
n
0
an
d
5
V
.
•
Betw
ee
n
4
an
d
5:
5
V
R
epl
ac
e
ind
oo
r f
an
m
ot
or
.
R
ep
lac
e
in
do
or
fa
n
m
ot
or
.
C
or
re
ct
c
on
ne
ct
or
c
on
ne
ct
io
n.
R
epl
ac
e
ind
oo
r f
an
m
ot
or
.
R
ep
la
ce
in
do
or
fa
n
m
ot
or
.
C
he
ck
in
do
or
P
.C
. b
oa
rd
(M
C
C
-1
40
2, MC
C
-1
57
0)
.
Fai
lu
re
Repl
ac
e
Y
es
es
ua
C
e
ma
n
ed
oc
kc
eh
C
ed
oc
kc
eh
C
W
at
er
o
ve
rfl
ow
in
a
n
in
do
or
u
ni
t
1.
F
lo
at
S
W
m
al
fu
nc
tio
n
2.
D
ra
in
p
um
p
m
al
fu
nc
tio
n
3.
C
lo
gg
in
g
of
d
ra
in
p
ip
e
4.
In
do
or
P
.C
. b
oa
rd
e
rro
r
S
ub
-c
od
e:
O
ve
rfl
ow
in
g
in
do
or
u
ni
t's
a
dd
re
ss
Y
es
Ye
s
Ye
s
No
C
he
ck
d
ra
in
p
ip
e,
e
tc
.
* C
he
ck
the
re
is
2
20
V
v
ol
ta
ge
o
f 1
-3
p
in
o
f C
N
67
o
n
in
do
or
P
.C
. b
oa
rd
.
D
oe
s
dr
ai
n
pu
m
p
op
era
te
?
D
oe
s
flo
at
S
W
op
er
at
e?
Is
fl
oa
t S
W
co
nn
ec
to
r (
In
do
or
co
ntr
ol
P
.C
. b
oa
rd
C
N3
4)
co
nn
ect
ed
n
or
m
ally
?
No
No
R
ep
la
ce
d
ra
in
p
um
p,
a
nd
c
he
ck
c
ab
lin
g.
Is
p
ow
er
su
pp
ly
to
d
ra
in
pu
m
p
no
rm
al
?*
Is
w
iri
ng
n
or
m
al
?
C
or
re
ct
c
on
ne
ct
or
c
on
ne
ct
io
n.
C
he
ck
a
nd
c
or
re
ct
w
iri
ng
.
C
he
ck
in
do
or
P.C
. b
oa
rd
.
Fa
ilu
re
Re
pla
ce
C
he
ck
in
do
or
P.
C
. b
oa
rd
.
Fa
ilu
re
Re
pla
ce
No
Y
es
Y
es
No
135