Cable Tray Sizing Example
To determine the proper tray size based on 25% fill, use the following calculation
for cable with outer diameter of 0.30 inches (8 mm):
1.
Determine cable diameter and total number of cables
0.30" diameter each
100 cables total
(8 mm diameter)
2.
Square the cable diameter
0.30 x 0.30 = .09
(8 x 8 = 64)
3.
Multiply result by number of cables
0.09 x 100 = 9
(64 x 100 = 6400)
4.
Multiply result by 0.785 to factor for cable roundness
This result is the total cross-sectional area of your cables
9 x 0.785 = 7.065 sq in
(6400 x 0.785 = 5024 sq mm)
5.
Multiply result by 4 to obtain pathway size at 25% fill
7.065 x 4 = 28.26 sq in
(5024 x 4 = 20096 sq mm)
At 25% fill, a 28 sq in (20096 sq mm) area is needed,
so a standard 4" x 8" (102 x 203 mm) tray would be adequate.
Note: For conduit, size for 40% fill by substituting 2.5 as the multiplier in Step 5
Cable OD
2
x
No. of cables
=
y
y
x
0.785
=
z
z
x
4
=
Pathway size at 25% fill
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Cable Tray Sizing Example
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